Data:L10a16/Multivariable Alexander: Difference between revisions

Revision as of 11:51, 6 May 2009

${\frac {3uv^{2}-6uv+2u+2v^{3}-6v^{2}+3v}{{\sqrt {u}}v^{3/2}}}$

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	<math>-2 u^3-3 v u^2+6 u^2+6 v u~~-3 u-2~~ v</math>		<math>\frac{3 u v^2-6 u v+2 u+2 v^3-6 v^2+3 v}{\sqrt{u} v^{3/2}}</math>