Data:L10a8/Multivariable Alexander: Difference between revisions

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<math>-\frac{(u-1) (v-1) \left(v^4-2 v^3+4 v^2-2 v+1\right)}{\sqrt{u} v^{5/2}}</math>
<math>-\frac{(t(1)-1) (t(2)-1) \left(t(2)^4-2 t(2)^3+4 t(2)^2-2 t(2)+1\right)}{\sqrt{t(1)} t(2)^{5/2}}</math>

Latest revision as of 17:40, 20 February 2013