Data:L11a10/Multivariable Alexander: Difference between revisions

Revision as of 11:54, 6 May 2009

${\frac {(u-1)(v-1)\left(4v^{2}-7v+4\right)}{{\sqrt {u}}v^{3/2}}}$

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	<math>-4 v ~~u^3+~~4 ~~u^3+11~~ v u^2-~~11 u^2-11~~ v u+11 u+4 v-4</math>		<math>\frac{(u-1) (v-1) \left(4 v^2-7 v+4\right)}{\sqrt{u} v^{3/2}}</math>