Data:L11a32/Multivariable Alexander: Difference between revisions

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<math>\frac{2 u v^3-9 u v^2+12 u v-6 u-6 v^3+12 v^2-9 v+2}{\sqrt{u} v^{3/2}}</math>
<math>\frac{2 t(1) t(2)^3-6 t(2)^3-9 t(1) t(2)^2+12 t(2)^2+12 t(1) t(2)-9 t(2)-6 t(1)+2}{\sqrt{t(1)} t(2)^{3/2}}</math>

Latest revision as of 17:39, 20 February 2013