Data:L11a53/Multivariable Alexander: Difference between revisions

Latest revision as of 11:54, 6 May 2009

${\frac {(u-1)(v-1)\left(v^{2}+1\right)\left(2v^{2}-3v+2\right)}{{\sqrt {u}}v^{5/2}}}$

Revision as of 23:02, 8 September 2005 (view source) DrorsRobot (talk \| contribs) No edit summary		Latest revision as of 11:54, 6 May 2009 (view source) DrorsRobot (talk \| contribs) No edit summary
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	<math>-2 v ~~u^5+2 u^5+5 v u^4-5 u^4~~-7 v u^3+7 ~~u^3+7~~ v u^2-~~7 u^2-5~~ v u+5 u+2 v-2</math>		<math>\frac{(u-1) (v-1) \left(v^2+1\right) \left(2 v^2-3 v+2\right)}{\sqrt{u} v^{5/2}}</math>