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<math>\frac{-2 u v^2 w^3+2 u v^2 w^2-u v^2 w+2 u v w^3-4 u v w^2+3 u v w-u v+u w^2-u w+v^2 w^3-v^2 w^2+v w^4-3 v w^3+4 v w^2-2 v w+w^3-2 w^2+2 w}{\sqrt{u} v w^2}</math> |
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<math>\frac{t(2) t(3)^4-2 t(1) t(2)^2 t(3)^3+t(2)^2 t(3)^3+2 t(1) t(2) t(3)^3-3 t(2) t(3)^3+t(3)^3+2 t(1) t(2)^2 t(3)^2-t(2)^2 t(3)^2+t(1) t(3)^2-4 t(1) t(2) t(3)^2+4 t(2) t(3)^2-2 t(3)^2-t(1) t(2)^2 t(3)-t(1) t(3)+3 t(1) t(2) t(3)-2 t(2) t(3)+2 t(3)-t(1) t(2)}{\sqrt{t(1)} t(2) t(3)^2}</math> |
Latest revision as of 16:57, 20 February 2013
