( t ( 1 ) t ( 2 ) t ( 3 ) + 1 ) ( t ( 3 ) 2 − t ( 1 ) t ( 2 ) ) t ( 1 ) t ( 2 ) t ( 3 ) 3 / 2 {\displaystyle {\frac {(t(1)t(2)t(3)+1)\left(t(3)^{2}-t(1)t(2)\right)}{t(1)t(2)t(3)^{3/2}}}}
