( t ( 1 ) − 1 ) ( t ( 2 ) − 1 ) ( t ( 3 ) − 1 ) ( 2 t ( 3 ) 2 − 3 t ( 3 ) + 2 ) t ( 1 ) t ( 2 ) t ( 3 ) 3 / 2 {\displaystyle {\frac {(t(1)-1)(t(2)-1)(t(3)-1)\left(2t(3)^{2}-3t(3)+2\right)}{{\sqrt {t(1)}}{\sqrt {t(2)}}t(3)^{3/2}}}}
