( t ( 2 ) 2 − 3 t ( 2 ) + 1 ) ( t ( 1 ) 2 t ( 2 ) 2 + t ( 1 ) t ( 2 ) + 1 ) t ( 1 ) t ( 2 ) 2 {\displaystyle {\frac {\left(t(2)^{2}-3t(2)+1\right)\left(t(1)^{2}t(2)^{2}+t(1)t(2)+1\right)}{t(1)t(2)^{2}}}}
