Data:L10n94/Multivariable Alexander: Difference between revisions

Revision as of 11:53, 6 May 2009

[math]\displaystyle{ \frac{(u v w+1) \left(w^2-u v\right)}{u v w^{3/2}} }[/math]

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	<math>u w ~~v^3+v~~^2-u~~^2 w^2~~ v-u w</math>		<math>\frac{(u v w+1) \left(w^2-u v\right)}{u v w^{3/2}}</math>