Data:L11a6/Multivariable Alexander: Difference between revisions

Latest revision as of 10:54, 6 May 2009

${\frac {(u-1)(v-1)\left(2v^{4}-4v^{3}+5v^{2}-4v+2\right)}{{\sqrt {u}}v^{5/2}}}$

Revision as of 22:00, 8 September 2005 (view source) DrorsRobot (talk \| contribs) No edit summary		Latest revision as of 10:54, 6 May 2009 (view source) DrorsRobot (talk \| contribs) No edit summary
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	<math>-2 v ~~u^5+~~2 ~~u^5+6~~ v u^4-~~6 u^~~4-9 v u^3+~~9 u^3+9~~ v u^2-~~9 u^2-6~~ v u+6 u+2 v-2</math>		<math>\frac{(u-1) (v-1) \left(2 v^4-4 v^3+5 v^2-4 v+2\right)}{\sqrt{u} v^{5/2}}</math>