Data:L11a130/Multivariable Alexander: Difference between revisions

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<math>-2 v u^5+2 u^5+4 v u^4-4 u^4-6 v u^3+6 u^3+6 v u^2-6 u^2-4 v u+4 u+2 v-2</math>
<math>-\frac{2 (u-1) (v-1) \left(v^2+1\right) \left(v^2-v+1\right)}{\sqrt{u} v^{5/2}}</math>

Revision as of 10:55, 6 May 2009