Data:L11a346/Multivariable Alexander: Difference between revisions

Revision as of 11:57, 6 May 2009

[math]\displaystyle{ \frac{(u-1) (v-1) \left(u^2 v^2-4 u^2 v+u^2+u v+v^2-4 v+1\right)}{u^{3/2} v^{3/2}} }[/math]

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	<math>-~~v^3 u^3+5~~ v~~^2 u^3~~-~~5 v u^3+u^3+v^3~~ u^2-6 v^2 u^2+6 v u^2-u~~^2-~~v~~^3 u~~+6 v^2 u-6 v u+u+v^3-5 v^2~~+5 v-1~~</math>		<math>\frac{(u-1) (v-1) \left(u^2 v^2-4 u^2 v+u^2+u v+v^2-4 v+1\right)}{u^{3/2} v^{3/2}}</math>