Talk:The Multivariable Alexander Polynomial: Difference between revisions

From Knot Atlas
Jump to navigationJump to search
(comment)
 
m (Reverted edits by CvaroUc4tr (Talk); changed back to last version by Drorbn)
 
(6 intermediate revisions by 4 users not shown)
Line 3: Line 3:
:Dror doesn't understand the multivariable Alexander polynomial well enough to give simple topological reasons for the vanishing of the said polynomial for these knots.
:Dror doesn't understand the multivariable Alexander polynomial well enough to give simple topological reasons for the vanishing of the said polynomial for these knots.


The multivariable Alexander polynomial is zero precisely when H1 of the universal abelian cover has non-zero rank (as a module over the group-ring of covering transformations). Equivalently, if H2 of the universal abelian cover is non-trivial. In this case, H2 is free on one generator, which is represented by a map of a genus 2 surface into the link complement. So far I haven't found a very appealing description of this surface, but it's there...
The multivariable Alexander polynomial is zero precisely when <math>H_1</math> of the universal Abelian cover has non-zero rank (as a module over the group-ring of covering transformations). Equivalently, if <math>H_2</math> of the universal Abelian cover is non-trivial. In the [[L10n36]] case, <math>H_2</math> is free on one generator, which is represented by a map of a genus 2 surface into the link complement. So far I haven't found a very appealing description of this surface, but it's there... -Ryan Budney

Latest revision as of 16:24, 27 May 2009

Regarding this comment:

Dror doesn't understand the multivariable Alexander polynomial well enough to give simple topological reasons for the vanishing of the said polynomial for these knots.

The multivariable Alexander polynomial is zero precisely when of the universal Abelian cover has non-zero rank (as a module over the group-ring of covering transformations). Equivalently, if of the universal Abelian cover is non-trivial. In the L10n36 case, is free on one generator, which is represented by a map of a genus 2 surface into the link complement. So far I haven't found a very appealing description of this surface, but it's there... -Ryan Budney