Data:L11a526/Multivariable Alexander: Difference between revisions
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<math>\frac{(t(3)-1) \left(-t(2)^2 t(1)^2+t(2) t(3)^2 t(1)^2-t(3)^2 t(1)^2+2 t(2) t(1)^2-2 t(2) t(3) t(1)^2+t(3) t(1)^2-t(1)^2+2 t(2)^2 t(1)+t(2)^2 t(3)^2 t(1)-3 t(2) t(3)^2 t(1)+2 t(3)^2 t(1)-3 t(2) t(1)-2 t(2)^2 t(3) t(1)+6 t(2) t(3) t(1)-2 t(3) t(1)+t(1)-t(2)^2-t(2)^2 t(3)^2+2 t(2) t(3)^2-t(3)^2+t(2)+t(2)^2 t(3)-2 t(2) t(3)\right)}{t(1) t(2) t(3)^{3/2}}</math> |
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Latest revision as of 16:26, 20 February 2013
[math]\displaystyle{ \frac{(t(3)-1) \left(-t(2)^2 t(1)^2+t(2) t(3)^2 t(1)^2-t(3)^2 t(1)^2+2 t(2) t(1)^2-2 t(2) t(3) t(1)^2+t(3) t(1)^2-t(1)^2+2 t(2)^2 t(1)+t(2)^2 t(3)^2 t(1)-3 t(2) t(3)^2 t(1)+2 t(3)^2 t(1)-3 t(2) t(1)-2 t(2)^2 t(3) t(1)+6 t(2) t(3) t(1)-2 t(3) t(1)+t(1)-t(2)^2-t(2)^2 t(3)^2+2 t(2) t(3)^2-t(3)^2+t(2)+t(2)^2 t(3)-2 t(2) t(3)\right)}{t(1) t(2) t(3)^{3/2}} }[/math]