Data:L11a10/Multivariable Alexander: Difference between revisions

Latest revision as of 15:40, 20 February 2013

${\frac {(t(1)-1)(t(2)-1)\left(4t(2)^{2}-7t(2)+4\right)}{{\sqrt {t(1)}}t(2)^{3/2}}}$

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	<math>-4 v ~~u^3+~~4 ~~u^3+11 v u~~^2-11 u^2~~-11 v u+11 u~~+4 ~~v-4~~</math>		<math>\frac{(t(1)-1) (t(2)-1) \left(4 t(2)^2-7 t(2)+4\right)}{\sqrt{t(1)} t(2)^{3/2}}</math>