Data:L8a13/Multivariable Alexander: Difference between revisions

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<math>-\frac{(u+v) \left(u^2 v+u v^2-2 u v+u+v\right)}{u^{3/2} v^{3/2}}</math>
<math>-\frac{(t(1)+t(2)) \left(t(2) t(1)^2+t(2)^2 t(1)-2 t(2) t(1)+t(1)+t(2)\right)}{t(1)^{3/2} t(2)^{3/2}}</math>

Latest revision as of 15:54, 20 February 2013