Data:L11a491/Multivariable Alexander: Difference between revisions

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<math>-\frac{(v-1) (w-1) \left(2 u w^3-2 u w^2+2 u w-u+w^4-2 w^3+2 w^2-2 w\right)}{\sqrt{u} \sqrt{v} w^{5/2}}</math>
<math>-\frac{(t(2)-1) (t(3)-1) \left(t(3)^4+2 t(1) t(3)^3-2 t(3)^3-2 t(1) t(3)^2+2 t(3)^2+2 t(1) t(3)-2 t(3)-t(1)\right)}{\sqrt{t(1)} \sqrt{t(2)} t(3)^{5/2}}</math>

Latest revision as of 16:04, 20 February 2013

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