Data:L10n19/Multivariable Alexander: Difference between revisions

Latest revision as of 15:15, 20 February 2013

${\frac {2t(1)t(2)^{3}-4t(1)t(2)^{2}+t(2)^{2}+t(1)t(2)-4t(2)+2}{{\sqrt {t(1)}}t(2)^{3/2}}}$

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	<math>-2 v u^3+4 v u^2-u^2-v u+4 u-2</math>		<math>\frac{2 t(1) t(2)^3-4 t(1) t(2)^2+t(2)^2+t(1) t(2)-4 t(2)+2}{\sqrt{t(1)} t(2)^{3/2}}</math>