Data:L11n26/Multivariable Alexander: Difference between revisions

Latest revision as of 15:26, 20 February 2013

$-{\frac {4t(1)t(2)^{3}-4t(1)t(2)^{2}+t(2)^{2}+t(1)t(2)-4t(2)+4}{{\sqrt {t(1)}}t(2)^{3/2}}}$

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	<math>-4 v u^3+4 v u^2-u^2-v u+4 ~~u-4~~</math>		<math>-\frac{4 t(1) t(2)^3-4 t(1) t(2)^2+t(2)^2+t(1) t(2)-4 t(2)+4}{\sqrt{t(1)} t(2)^{3/2}}</math>