Data:L9n19/Multivariable Alexander: Difference between revisions

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<math>-\frac{\left(u^2+v\right) \left(u v^2+1\right)}{u^{3/2} v^{3/2}}</math>
<math>-\frac{\left(t(1)^2+t(2)\right) \left(t(1) t(2)^2+1\right)}{t(1)^{3/2} t(2)^{3/2}}</math>

Latest revision as of 15:49, 20 February 2013