Data:L10a49/Multivariable Alexander: Difference between revisions

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<math>-\frac{4 u v^4-6 u v^3+6 u v^2-4 u v+u+v^5-4 v^4+6 v^3-6 v^2+4 v}{\sqrt{u} v^{5/2}}</math>
<math>-\frac{t(2)^5+4 t(1) t(2)^4-4 t(2)^4-6 t(1) t(2)^3+6 t(2)^3+6 t(1) t(2)^2-6 t(2)^2-4 t(1) t(2)+4 t(2)+t(1)}{\sqrt{t(1)} t(2)^{5/2}}</math>

Latest revision as of 16:55, 20 February 2013