Data:L11a129/Multivariable Alexander: Difference between revisions

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<math>\frac{2 u v^3-6 u v^2+6 u v-3 u-3 v^3+6 v^2-6 v+2}{\sqrt{u} v^{3/2}}</math>
<math>\frac{2 t(1) t(2)^3-3 t(2)^3-6 t(1) t(2)^2+6 t(2)^2+6 t(1) t(2)-6 t(2)-3 t(1)+2}{\sqrt{t(1)} t(2)^{3/2}}</math>

Latest revision as of 17:51, 20 February 2013