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<math>\frac{u v^2 w^2-3 u v^2 w+3 u v^2-3 u v w^2+8 u v w-5 u v+3 u w^2-5 u w+2 u-2 v^2 w^2+5 v^2 w-3 v^2+5 v w^2-8 v w+3 v-3 w^2+3 w-1}{\sqrt{u} v w}</math> |
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<math>\frac{t(1) t(3)^2 t(2)^2-2 t(3)^2 t(2)^2+3 t(1) t(2)^2-3 t(1) t(3) t(2)^2+5 t(3) t(2)^2-3 t(2)^2-3 t(1) t(3)^2 t(2)+5 t(3)^2 t(2)-5 t(1) t(2)+8 t(1) t(3) t(2)-8 t(3) t(2)+3 t(2)+3 t(1) t(3)^2-3 t(3)^2+2 t(1)-5 t(1) t(3)+3 t(3)-1}{\sqrt{t(1)} t(2) t(3)}</math> |
Latest revision as of 15:42, 20 February 2013
