Data:L11a534/Multivariable Alexander: Difference between revisions
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<math>\frac{ |
<math>\frac{t(1) t(4)^2 t(3)^2+t(2) t(4)^2 t(3)^2-t(4)^2 t(3)^2+t(1) t(3)^2-t(1) t(2) t(3)^2+2 t(2) t(3)^2-2 t(1) t(4) t(3)^2+t(1) t(2) t(4) t(3)^2-3 t(2) t(4) t(3)^2+2 t(4) t(3)^2-t(3)^2-3 t(1) t(4)^2 t(3)+t(1) t(2) t(4)^2 t(3)-2 t(2) t(4)^2 t(3)+2 t(4)^2 t(3)-2 t(1) t(3)+2 t(1) t(2) t(3)-3 t(2) t(3)+6 t(1) t(4) t(3)-4 t(1) t(2) t(4) t(3)+6 t(2) t(4) t(3)-4 t(4) t(3)+t(3)+2 t(1) t(4)^2-t(1) t(2) t(4)^2+t(2) t(4)^2-t(4)^2+t(1)-t(1) t(2)+t(2)-3 t(1) t(4)+2 t(1) t(2) t(4)-2 t(2) t(4)+t(4)}{\sqrt{t(1)} \sqrt{t(2)} t(3) t(4)}</math> |
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Latest revision as of 15:26, 20 February 2013
[math]\displaystyle{ \frac{t(1) t(4)^2 t(3)^2+t(2) t(4)^2 t(3)^2-t(4)^2 t(3)^2+t(1) t(3)^2-t(1) t(2) t(3)^2+2 t(2) t(3)^2-2 t(1) t(4) t(3)^2+t(1) t(2) t(4) t(3)^2-3 t(2) t(4) t(3)^2+2 t(4) t(3)^2-t(3)^2-3 t(1) t(4)^2 t(3)+t(1) t(2) t(4)^2 t(3)-2 t(2) t(4)^2 t(3)+2 t(4)^2 t(3)-2 t(1) t(3)+2 t(1) t(2) t(3)-3 t(2) t(3)+6 t(1) t(4) t(3)-4 t(1) t(2) t(4) t(3)+6 t(2) t(4) t(3)-4 t(4) t(3)+t(3)+2 t(1) t(4)^2-t(1) t(2) t(4)^2+t(2) t(4)^2-t(4)^2+t(1)-t(1) t(2)+t(2)-3 t(1) t(4)+2 t(1) t(2) t(4)-2 t(2) t(4)+t(4)}{\sqrt{t(1)} \sqrt{t(2)} t(3) t(4)} }[/math]