Data:L11a41/Multivariable Alexander: Difference between revisions

Revision as of 10:54, 6 May 2009

${\frac {(u-1)(v-1)^{3}\left(v^{2}-3v+1\right)}{{\sqrt {u}}v^{5/2}}}$

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	<math>-~~v u^5+u^5+6~~ v ~~u^4~~-~~6 u^4-13 v u~~^3~~+13 u^3+13~~ v u^2-~~13 u^2-6~~ v u+6 u+v-1</math>		<math>\frac{(u-1) (v-1)^3 \left(v^2-3 v+1\right)}{\sqrt{u} v^{5/2}}</math>