Data:L11a320/Multivariable Alexander: Difference between revisions

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<math>-\frac{(u v-u+1) (u v-v+1) (2 u v-u-v+2)}{u^{3/2} v^{3/2}}</math>
<math>-\frac{(t(2) t(1)-t(1)+1) (t(1) t(2)-t(2)+1) (2 t(2) t(1)-t(1)-t(2)+2)}{t(1)^{3/2} t(2)^{3/2}}</math>

Latest revision as of 15:59, 20 February 2013