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<math>\frac{2 u v w^4-2 u v w^3+2 u v w^2-2 u v w+u v+u w^5-3 u w^4+3 u w^3-3 u w^2+3 u w-u+v w^5-3 v w^4+3 v w^3-3 v w^2+3 v w-v-w^5+2 w^4-2 w^3+2 w^2-2 w}{\sqrt{u} \sqrt{v} w^{5/2}}</math> |
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<math>\frac{t(1) t(3)^5+t(2) t(3)^5-t(3)^5-3 t(1) t(3)^4+2 t(1) t(2) t(3)^4-3 t(2) t(3)^4+2 t(3)^4+3 t(1) t(3)^3-2 t(1) t(2) t(3)^3+3 t(2) t(3)^3-2 t(3)^3-3 t(1) t(3)^2+2 t(1) t(2) t(3)^2-3 t(2) t(3)^2+2 t(3)^2+3 t(1) t(3)-2 t(1) t(2) t(3)+3 t(2) t(3)-2 t(3)-t(1)+t(1) t(2)-t(2)}{\sqrt{t(1)} \sqrt{t(2)} t(3)^{5/2}}</math> |
Latest revision as of 15:28, 20 February 2013
