Data:L10a31/Multivariable Alexander: Difference between revisions

Revision as of 10:51, 6 May 2009

${\frac {(u-1)(v-1)\left(2v^{2}-3v+2\right)}{{\sqrt {u}}v^{3/2}}}$

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	<math>-2 v ~~u^3+~~2 ~~u^3+5~~ v u^2-~~5 u^2-5~~ v u+5 u+2 v-2</math>		<math>\frac{(u-1) (v-1) \left(2 v^2-3 v+2\right)}{\sqrt{u} v^{3/2}}</math>