Data:L11a102/Multivariable Alexander: Difference between revisions

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<math>-2 v u^5+2 u^5+5 v u^4-5 u^4-8 v u^3+8 u^3+8 v u^2-8 u^2-5 v u+5 u+2 v-2</math>
<math>\frac{(u-1) (v-1) \left(v^2-v+1\right) \left(2 v^2-v+2\right)}{\sqrt{u} v^{5/2}}</math>

Revision as of 10:55, 6 May 2009