Data:L11a493/Multivariable Alexander: Difference between revisions

Revision as of 10:59, 6 May 2009

[math]\displaystyle{ \frac{(u-1) (w-1) \left(w^2-w+1\right) \left(v w^2-2 v w+2 w-1\right)}{\sqrt{u} \sqrt{v} w^{5/2}} }[/math]

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	<math>v u^5-v w ~~u^5~~-~~4 v u^4+4 v~~ w u^4-2 w ~~u^4~~+~~2 u^4+6~~ v u^3-6 v w ~~u^3~~+5 w ~~u^3~~-5 u~~^3-5~~ v u^2+5 ~~v w u^~~2~~-6 w u^2+6 u^2+2 v u-2 v w u+4 w u-4 u-w+1~~</math>		<math>\frac{(u-1) (w-1) \left(w^2-w+1\right) \left(v w^2-2 v w+2 w-1\right)}{\sqrt{u} \sqrt{v} w^{5/2}}</math>