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<math>-\frac{u^3 v^5-u^3 v^4+u^3 v^3-u^3 v^2-u^2 v^5+3 u^2 v^4-3 u^2 v^3+3 u^2 v^2-u^2 v-u v^4+3 u v^3-3 u v^2+3 u v-u-v^3+v^2-v+1}{u^{3/2} v^{5/2}}</math> |
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<math>-\frac{t(1)^3 t(2)^5-t(1)^2 t(2)^5-t(1)^3 t(2)^4+3 t(1)^2 t(2)^4-t(1) t(2)^4+t(1)^3 t(2)^3-3 t(1)^2 t(2)^3+3 t(1) t(2)^3-t(2)^3-t(1)^3 t(2)^2+3 t(1)^2 t(2)^2-3 t(1) t(2)^2+t(2)^2-t(1)^2 t(2)+3 t(1) t(2)-t(2)-t(1)+1}{t(1)^{3/2} t(2)^{5/2}}</math> |
Latest revision as of 15:03, 20 February 2013
