Data:L11a130/Multivariable Alexander: Difference between revisions

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<math>-\frac{2 (u-1) (v-1) \left(v^2+1\right) \left(v^2-v+1\right)}{\sqrt{u} v^{5/2}}</math>
<math>-\frac{2 (t(1)-1) (t(2)-1) \left(t(2)^2+1\right) \left(t(2)^2-t(2)+1\right)}{\sqrt{t(1)} t(2)^{5/2}}</math>

Latest revision as of 15:58, 20 February 2013