Data:L10a16/Multivariable Alexander: Difference between revisions

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<math>\frac{3 u v^2-6 u v+2 u+2 v^3-6 v^2+3 v}{\sqrt{u} v^{3/2}}</math>
<math>\frac{2 t(2)^3+3 t(1) t(2)^2-6 t(2)^2-6 t(1) t(2)+3 t(2)+2 t(1)}{\sqrt{t(1)} t(2)^{3/2}}</math>

Latest revision as of 15:59, 20 February 2013