Data:L11a528/Multivariable Alexander: Difference between revisions

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<math>\frac{(w-1) \left(u^2 v^2 w+u^2 v w^2-u^2 v w+u^2 v-u^2 w^2+u^2 w-u^2+u v^2 w^2-u v^2 w+u v^2-2 u v w^2-2 u v+u w^2-u w+u-v^2 w^2+v^2 w-v^2+v w^2-v w+v+w\right)}{u v w^{3/2}}</math>
<math>\frac{(t(3)-1) \left(t(2) t(3)^2 t(1)^2-t(3)^2 t(1)^2+t(2) t(1)^2+t(2)^2 t(3) t(1)^2-t(2) t(3) t(1)^2+t(3) t(1)^2-t(1)^2+t(2)^2 t(1)+t(2)^2 t(3)^2 t(1)-2 t(2) t(3)^2 t(1)+t(3)^2 t(1)-2 t(2) t(1)-t(2)^2 t(3) t(1)-t(3) t(1)+t(1)-t(2)^2-t(2)^2 t(3)^2+t(2) t(3)^2+t(2)+t(2)^2 t(3)-t(2) t(3)+t(3)\right)}{t(1) t(2) t(3)^{3/2}}</math>

Latest revision as of 16:30, 20 February 2013

[math]\displaystyle{ \frac{(t(3)-1) \left(t(2) t(3)^2 t(1)^2-t(3)^2 t(1)^2+t(2) t(1)^2+t(2)^2 t(3) t(1)^2-t(2) t(3) t(1)^2+t(3) t(1)^2-t(1)^2+t(2)^2 t(1)+t(2)^2 t(3)^2 t(1)-2 t(2) t(3)^2 t(1)+t(3)^2 t(1)-2 t(2) t(1)-t(2)^2 t(3) t(1)-t(3) t(1)+t(1)-t(2)^2-t(2)^2 t(3)^2+t(2) t(3)^2+t(2)+t(2)^2 t(3)-t(2) t(3)+t(3)\right)}{t(1) t(2) t(3)^{3/2}} }[/math]

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