Data:L11a138/Multivariable Alexander: Difference between revisions

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<math>-\frac{4 u v^3-12 u v^2+13 u v-4 u-4 v^3+13 v^2-12 v+4}{\sqrt{u} v^{3/2}}</math>
<math>-\frac{4 t(1) t(2)^3-4 t(2)^3-12 t(1) t(2)^2+13 t(2)^2+13 t(1) t(2)-12 t(2)-4 t(1)+4}{\sqrt{t(1)} t(2)^{3/2}}</math>

Latest revision as of 16:33, 20 February 2013