Data:L11n400/Multivariable Alexander: Difference between revisions

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<math>\frac{(w-1) \left(u v w^3-u v w^2+u v w+u v+u w^2-u w-v w^3+v w^2+w^4+w^3-w^2+w\right)}{\sqrt{u} \sqrt{v} w^{5/2}}</math>
<math>\frac{(t(3)-1) \left(t(3)^4+t(1) t(2) t(3)^3-t(2) t(3)^3+t(3)^3+t(1) t(3)^2-t(1) t(2) t(3)^2+t(2) t(3)^2-t(3)^2-t(1) t(3)+t(1) t(2) t(3)+t(3)+t(1) t(2)\right)}{\sqrt{t(1)} \sqrt{t(2)} t(3)^{5/2}}</math>

Latest revision as of 17:38, 20 February 2013

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