Data:L10a46/Multivariable Alexander
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[math]\displaystyle{ \frac{\left(v^2-v+1\right) \left(u v^3-u v^2+u v-2 u-2 v^3+v^2-v+1\right)}{\sqrt{u} v^{5/2}} }[/math]
[math]\displaystyle{ \frac{\left(v^2-v+1\right) \left(u v^3-u v^2+u v-2 u-2 v^3+v^2-v+1\right)}{\sqrt{u} v^{5/2}} }[/math]