Data:L11a308/Multivariable Alexander
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[math]\displaystyle{ \frac{\left(v^2-v+1\right) (u+v-1) (u v+1) (u v-u-v)}{u^{3/2} v^{5/2}} }[/math]
[math]\displaystyle{ \frac{\left(v^2-v+1\right) (u+v-1) (u v+1) (u v-u-v)}{u^{3/2} v^{5/2}} }[/math]