Data:L11n403/Multivariable Alexander
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[math]\displaystyle{ \frac{(v-1) (w-1) \left(w^4-u\right)}{\sqrt{u} \sqrt{v} w^{5/2}} }[/math]
[math]\displaystyle{ \frac{(v-1) (w-1) \left(w^4-u\right)}{\sqrt{u} \sqrt{v} w^{5/2}} }[/math]