( t ( 3 ) − 1 ) ( t ( 3 ) + 1 ) ( t ( 1 ) t ( 2 ) + t ( 3 ) ) t ( 1 ) t ( 2 ) t ( 3 ) 3 / 2 {\displaystyle {\frac {(t(3)-1)(t(3)+1)(t(1)t(2)+t(3))}{{\sqrt {t(1)}}{\sqrt {t(2)}}t(3)^{3/2}}}}