Data:L10a22/Multivariable Alexander: Difference between revisions

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<math>\frac{(u-1) (v-1)^3 \left(v^2-v+1\right)}{\sqrt{u} v^{5/2}}</math>
<math>\frac{(t(1)-1) (t(2)-1)^3 \left(t(2)^2-t(2)+1\right)}{\sqrt{t(1)} t(2)^{5/2}}</math>

Latest revision as of 16:39, 20 February 2013