Data:L11a489/Multivariable Alexander: Difference between revisions

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<math>-\frac{(w-1) \left(2 u v w^3-3 u v w^2+2 u v w+3 u w^2-3 u w+u+v w^4-3 v w^3+3 v w^2+2 w^3-3 w^2+2 w\right)}{\sqrt{u} \sqrt{v} w^{5/2}}</math>
<math>-\frac{(t(3)-1) \left(t(2) t(3)^4+2 t(1) t(2) t(3)^3-3 t(2) t(3)^3+2 t(3)^3+3 t(1) t(3)^2-3 t(1) t(2) t(3)^2+3 t(2) t(3)^2-3 t(3)^2-3 t(1) t(3)+2 t(1) t(2) t(3)+2 t(3)+t(1)\right)}{\sqrt{t(1)} \sqrt{t(2)} t(3)^{5/2}}</math>

Latest revision as of 16:36, 20 February 2013

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