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<math>\frac{-2 u v w^4+2 u v w^3-2 u v w^2+2 u v w-u v+u w^4-u w^3+u w^2-u w+v w^4-v w^3+v w^2-v w+w^5-2 w^4+2 w^3-2 w^2+2 w}{\sqrt{u} \sqrt{v} w^{5/2}}</math> |
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<math>\frac{t(3)^5+t(1) t(3)^4-2 t(1) t(2) t(3)^4+t(2) t(3)^4-2 t(3)^4-t(1) t(3)^3+2 t(1) t(2) t(3)^3-t(2) t(3)^3+2 t(3)^3+t(1) t(3)^2-2 t(1) t(2) t(3)^2+t(2) t(3)^2-2 t(3)^2-t(1) t(3)+2 t(1) t(2) t(3)-t(2) t(3)+2 t(3)-t(1) t(2)}{\sqrt{t(1)} \sqrt{t(2)} t(3)^{5/2}}</math> |
Latest revision as of 17:59, 20 February 2013
