Data:L11n75/Multivariable Alexander: Difference between revisions

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<math>-\frac{2 u v^3-2 u v^2-u v+2 u+2 v^5-v^4-2 v^3+2 v^2}{\sqrt{u} v^{5/2}}</math>
<math>-\frac{2 t(2)^5-t(2)^4+2 t(1) t(2)^3-2 t(2)^3-2 t(1) t(2)^2+2 t(2)^2-t(1) t(2)+2 t(1)}{\sqrt{t(1)} t(2)^{5/2}}</math>

Latest revision as of 16:52, 20 February 2013