Structure and Operations

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(For In[1] see Setup)

In[2]:= ?Crossings

Crossings[L] returns the number of crossings of a knot/link L (in its given presentation).

In[3]:= ?PositiveCrossings

PositiveCrossings[L] returns the number of positive (right handed) crossings in a knot/link L (in its given presentation).

In[4]:= ?NegativeCrossings

NegativeCrossings[L] returns the number of negaitve (left handed) crossings in a knot/link L (in its given presentation).

Thus here's one tautology and one easy example:

In[5]:=

Crossings /@ {Knot[0, 1], TorusKnot[11,10]}

Out[5]=
{0, 99}

And another easy example:

In[6]:=

K=Knot[6, 2]; {PositiveCrossings[K], NegativeCrossings[K]}

Out[6]=
{2, 4}
In[7]:= ?PositiveQ

PositiveQ[xing] returns True if xing is a positive (right handed) crossing and False if it is negative (left handed).

In[8]:= ?NegativeQ

NegativeQ[xing] returns True if xing is a negative (left handed) crossing and False if it is positive (right handed).

For example,

In[9]:=

PositiveQ /@ {X[1,3,2,4], X[1,4,2,3], Xp[1,3,2,4], Xp[1,4,2,3]}

Out[9]=
{False, True, True, True}
In[10]:= ?ConnectedSum

ConnectedSum[K1, K2] represents the connected sum of the knots K1 and K2 (ConnectedSum may not work with links).

The connected sum of the knot 4_1 with itself has 8 crossings (unsurprisingly):

In[11]:=

K = ConnectedSum[Knot[4,1], Knot[4,1]]

Out[11]=
ConnectedSum[Knot[4, 1], Knot[4, 1]]
In[12]:=

Crossings[K]

Out[12]=
8

It is also nice to know that, as expected, the Jones polynomial of is the square of the Jones polynomial of 4_1:


In[13]:=

Jones[K][q] == Expand[Jones[Knot[4,1]][q]^2]

Out[13]=
True

It is less nice to know that the Jones polynomial cannot tell apart from the knot 8_9:

In[14]:=

Jones[K][q] == Jones[Knot[8,9]][q]

Out[14]=
True

But isn't equivalent to 8_9; indeed, their Alexander polynomials are different:

In[15]:=

{Alexander[K][t], Alexander[Knot[8,9]][t]}

Out[15]=
       -2   6          2       -3   3    5            2    3
{11 + t   - - - 6 t + t , 7 - t   + -- - - - 5 t + 3 t  - t }
            t                        2   t
                                    t