Data:L10a149/Multivariable Alexander
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[math]\displaystyle{ \frac{(t(1)-1) (t(3)-1)^2 (2 t(3) t(2)-t(2)-t(3)+2)}{\sqrt{t(1)} \sqrt{t(2)} t(3)^{3/2}} }[/math]
[math]\displaystyle{ \frac{(t(1)-1) (t(3)-1)^2 (2 t(3) t(2)-t(2)-t(3)+2)}{\sqrt{t(1)} \sqrt{t(2)} t(3)^{3/2}} }[/math]