Data:L11a209/Multivariable Alexander
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[math]\displaystyle{ \frac{\left(2 v^2-3 v+2\right) (u v-u+1) (u v-v+1)}{u v^2} }[/math]
[math]\displaystyle{ \frac{\left(2 v^2-3 v+2\right) (u v-u+1) (u v-v+1)}{u v^2} }[/math]