Data:L11a4/Multivariable Alexander
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[math]\displaystyle{ \frac{(t(1)-1) (t(2)-1) \left(2 t(2)^4-4 t(2)^3+5 t(2)^2-4 t(2)+2\right)}{\sqrt{t(1)} t(2)^{5/2}} }[/math]
[math]\displaystyle{ \frac{(t(1)-1) (t(2)-1) \left(2 t(2)^4-4 t(2)^3+5 t(2)^2-4 t(2)+2\right)}{\sqrt{t(1)} t(2)^{5/2}} }[/math]