Data:L11a519/Multivariable Alexander
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[math]\displaystyle{ \frac{(t(2)-1)^2 (t(3)-1) (t(3) t(1)-t(1)+1) (t(1) t(3)-t(3)+1)}{t(1) t(2) t(3)^{3/2}} }[/math]
[math]\displaystyle{ \frac{(t(2)-1)^2 (t(3)-1) (t(3) t(1)-t(1)+1) (t(1) t(3)-t(3)+1)}{t(1) t(2) t(3)^{3/2}} }[/math]